Discovery guide 43.1 Discovery guide
- kernel of T
the collection of all vectors \uvec{v} in the domain space V for which T(\uvec{v}) = \zerovec_W
- \ker T
notation for the kernel of T
- image of T
the collection of all image vectors T(\uvec{v}) in the codomain space W
- \im T
notation for the image of T
Discovery 43.1. Kernel of a matrix transformation.
Consider matrix transformation \funcdef{T_A}{\R^n}{\R^m} defined, as usual, by T_A(\uvec{x}) = A \uvec{x} for some m \times n matrix A\text{.}
(a)
Suppose A is a 4 \times 5 matrix whose RREF is
Determine a basis for \ker T_A as a subspace of \R^5\text{.}
(b)
Connect to previous concepts: \ker T_A is the same as the of A\text{.}
Discovery 43.2. Kernel examples.
In each of the following, describe the kernel vectors in words.
Try to use a more meaningful description than just βthe vectors that evaluate to zero in the transformationβ.
(a)
\funcdef{T}{\matrixring_n(\R)}{\matrixring_n(\R)} by T(A) = A - \utrans{A}\text{.}
(b)
Evaluation of polynomials at fixed x-value x = a\text{:}
\funcdef{E_a}{\poly(\R)}{\R^1} by E_a(p) = p(a) \text{.}
(c)
Differentiation: let F(a,b) represent the space of functions defined on the interval a \lt x \lt b\text{,} and let D(a,b) represent the subspace of F(a,b) consisting of differentiable functions.
Consider \funcdef{\ddx}{D(a,b)}{F(a,b)} by \ddx(f) = f'\text{.}
(d)
Integration: let C[a,b] represent the space of continuous functions defined on the interval a \le x \le b\text{.}
Consider \funcdef{I_{a,b}}{C[a,b]}{\R^1} by I_{a,b}(f) = \integral{a}{b}{f(x)}{x}\text{.}
Discovery 43.3. Determining kernel basis.
For each of the provided transformations of \matrixring_{2}(\R)\text{,} determine a basis for \ker T by carrying out the following steps.
- Starting with an arbitrary matrix\begin{equation*} X = \begin{bmatrix} a \amp b \\ c \amp d \end{bmatrix} \end{equation*}in \matrixring_{2}(\R)\text{,} determine conditions on parameters a,b,c,d so that T(X) = \zerovec \text{.}
- Use those conditions to reduce the number of parameters required to describe an arbitrary matrix in \ker T\text{.}
- Determine the basis vector associated to each in the reduced collection of parameters.
(a)
\funcdef{T = \trace}{\matrixring_{2}(\R)}{\R^1}\text{.}
(b)
\funcdef{T}{\matrixring_{2}(\R)}{\matrixring_{2}(\R)} by T(A) = A - \utrans{A}\text{.}
(c)
\funcdef{T = L_B}{\matrixring_{2}(\R)}{\matrixring_{2}(\R)} by L_B(A) = B A\text{,} where
Discovery 43.4. Image of a matrix transformation.
Consider matrix transformation \funcdef{T_A}{\R^n}{\R^m} defined, as usual, by T_A(\uvec{x}) = A \uvec{x} for some m \times n matrix A\text{.}
(a)
Apply the definition: An m-dimensional vector \uvec{b} is in \im T_A precisely when .
(b)
Connect to previous concepts: \im T_A is the same as the of A\text{.}
(c)
If you remembered the relevant previous concept in Task b, then hopefully you also remember how to determine a basis for that special space attached to matrix A\text{.}
Suppose A is a 4 \times 5 matrix whose RREF is
Describe how to determine a basis for \im T_A as a subspace of \R^4\text{.}
(d)
The matrix in Task c is the same as the one in Discovery 43.1.a. How does \dim (\ker T_A) relate to \dim (\im T_A)\text{?}
Discovery 43.5. Describing images.
Once again, for transformation \funcdef{T}{V}{W}\text{,} a vector \uvec{w} in W is in \im T precisely when there exists a vector \uvec{v} in V so that T(\uvec{v}) = \uvec{w}\text{.}
Suppose the domain space V is finite-dimensional with spanning set S = \{\uvec{v}_1,\uvec{v}_2,\uvec{v}_3\}\text{.}
(a)
Reword the above definition of \im T using these spanning vectors:
a vector \uvec{w} in W is in \im T precisely when there exists a of \uvec{v}_1,\uvec{v}_2,\uvec{v}_3 so that .
(b)
Reword the definition again in terms of the spanning image vectors:
a vector \uvec{w} in W is in \im T precisely when there exists a of T(\uvec{v}_1),T(\uvec{v}_2),T(\uvec{v}_3) so that .
(c)
Summarize: If \{\uvec{v}_1,\uvec{v}_2,\dotsc,\uvec{v}_m\} is a spanning set for V\text{,} then \{T(\uvec{v}_1),T(\uvec{v}_2),\dotsc,T(\uvec{v}_m)\} is for \im T\text{.}
Discovery 43.6. Image basis example.
Consider again the transformation \funcdef{T = L_B}{\matrixring_{2}(\R)}{\matrixring_{2}(\R)} from Discovery 43.3.c, defined by L_B(A) = B A for
Also recall the standard basis for \matrixring_{2}(\R)\text{:}
(a)
Compute the images of the standard basis vectors:
Discovery 43.5.c says these image vectors should form a spanning set for \im L_B\text{.} Do they form a basis for \im L_B\text{?}
(b)
Replace the first two standard basis vectors for V = \matrixring_{2}(\R) with your two basis vectors for \ker L_B that you computed in Discovery 43.3.c.
Write A_1,A_2 for these kernel vectors. Is \{A_1,A_2,E_{21},E_{22}\} still a basis for the domain space V = \matrixring_{2}(\R)\text{?}
If so, then \{T(A_1),T(A_2),T(E_{21}),T(E_{22})\} should again be a spanning set for \im L_B\text{.} Is it a basis for \im L_B\text{?} If not, can it easily be reduced to a basis for \im L_B\text{?}
(c)
Summarize the pattern: To determine a basis for the image of transformation \funcdef{T}{V}{W}\text{,} .
Discovery 43.7.
Create a linear transformation \funcdef{T}{\poly_3(\R)}{\matrixring_2(\R)} that has kernel precisely \Span \{ 1 + x^2, 1 - x^3 \}\text{.}
A transformation does not have to be specified by a formula; see Procedure 42.3.1.