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Section 12.1 Finite sets

Recall.

For m∈N we have defined the counting set
N<m={n∈N|n<m}={0,1,…,mβˆ’1}.
Clearly, N<m contains exactly m elements. In fact, we have defined the number m to be the set N<m. (See Example 11.4.2.)
As the terminology implies, we will use these sets to count the elements of other sets. In particular, given a set A, if we can match up the elements of A with the elements of N<m, one for one, then A must also contain exactly m elements.
finite set
a set A for which there exists a bijection N<mβ†’A for some m∈N, m>0

Remark 12.1.2.

Suppose A is finite. While there is only one number m for which a bijection N<m→A exists, there can be many such bijections, and the number of bijections increases as m increases.
cardinality (of a finite set A)
the unique natural number m for which a bijection N<m→A exists
|A|
the cardinality of the finite set A
cardA
alternative notation for the cardinality of the finite set A
#{…}
alternative notation for the cardinality of the set defined by {…}

Example 12.1.4.

For Ξ£={a,b,…,z}, we have |Ξ£|=26. Below are two example bijections Ο†,ψ:N<26β†’Ξ£ that verify this cardinality number.
Οƒ 0 1 2 3 β‹― 24 25
Ο†(Οƒ) a b c d β‹― y z
ψ(Οƒ) a z b y β‹― m n
Figure 12.1.5. Bijections Ο†,ψ:N<26β†’Ξ£ defined by a table of values.

Cardinality of an empty set.

What about the empty set? Clearly we should have |βˆ…|=0. But is this consistent with our definition of cardinality?
empty function
a function with domain βˆ…
If we accept the existence of an empty function βˆ…β†’X for every set X, then the properties of such functions that we need in order to establish |βˆ…|=0 will be vacuously true.
We are required to demonstrate an example of a bijection N<0β†’βˆ…. But
N<0={n∈N|n<0}=βˆ…,
so Statement 2 of Proposition 12.1.6 tells that the empty function N<0β†’βˆ… is indeed a bijection.