Determine the βdimensionβ of each of the following subspaces of \(\R^3\text{.}\) In each case, how does the number you come up with correspond with the answers youβve given throughout this activity?
Weβve been using the word βdimensionβ informally throughout our developlment of the concepts of vectors (e.g. calling vectors in \(\R^2\)two-dimensional vectors), but finally we can match our intuition about the βdimensionβ of the various types of subspaces of \(\R^3\) with the theoretical concepts of linear independence and spanning to make the following definition.
One way to obtain a basis for a space (and hence to determine its dimension) is to assign parameters β then each independent parameter corresponds to a basis vector.
For example, in \(\R^2\) we have natural parameters associated to the \(x\)- and \(y\)-coordinates: \(\uvec{x} = (x,y)\text{.}\) Expanding this into a linear combination, we get \(\uvec{x} = x(1,0) + y(0,1)\text{.}\) Parameter \(x\) corresponds to vector \((1,0)\) and parameter \(y\) corresponds to vector \((0,1)\text{,}\) and together the two corresponding vectors form a basis \(\{(1,0),(0,1)\}\) for \(\R^2\text{.}\) (In fact, the standard basis for \(\R^2\text{!}\)). Since there were two independent parameters required to described an arbitrary vector in the space, this led to two basis vectors, and so the dimension of \(\R^2\) is (surprise!) \(2\text{.}\)
In each of the following, determine a basis for the given space using the parameter method outlined above, similarly to the provided \(\R^2\) example. Then count the dimension of the space.
The subspace of \(\poly_5(\R)\) consisting of βevenβ polynomials; that is, those involving only even powers of \(x\) (and possibly a constant term).
A vector space is called finite-dimensional if it can be spanned by a finite set; otherwise, it is called infinite-dimensional. For example, \(\R^n\) is finite-dimensional for each value of \(n\text{,}\) because it can be spanned by the finite set of standard basis vectors \(\{\uvec{e}_1,\uvec{e}_2,\dotsc,\uvec{e}_n\}\text{.}\)
Weβve already seen that a linearly dependent spanning set can be reduced to a basis (PropositionΒ 18.5.1). Working the other way, we will use PropositionΒ 17.5.6 to argue in SubsectionΒ 19.5.2 that a linearly independent set that is not a spanning set can be built up to a basis by including additional vectors (PropositionΒ 19.5.4). PropositionΒ 17.5.6 tells us exactly how to do this: to ensure linear independence at each step, the new vector to be included should not be in the span of the old (in other words, the new should not be any linear combination of the old).
Hint. Since we now know the dimensions of these spaces, we know how many linearly independent vectors are required to form a basis. Just guess simple new vectors to include in the given set, one at a time, and for each make sure your new vector is not a linear combination of the vectors you already have. (You can check this by trying to solve an appropriate system of linear equations.)