Section 16.2 Basics: Discovery guide
Subsection Examples
Discovery 16.1.
For each of the following maps, verify that it is a homomorphism, and then either compute or try to describe the elements in the image and the elements in the kernel.
(a)
(b)
(c)
(d)
(e)
(Note: the group
(f)
(g)
(h)
(Note: You may skip the operation-preserving check for this example.)
(i)
(Note: You should perform the check that this map is operation-preserving geometrically. You still remember how to draw a geometric diagram of vector addition in
(j)
That is,
Subsection Some properties preserved by homomorphisms
Just as with isomorphisms, because a group homomorphismDiscovery 16.2. Homomorphism preserves identity.
Unfortunately the reasoning of Discovery 7.5 does not hold for homomorphisms because in that activity we relied on the bijective property. Here is some slightly more complicated reasoning that works in both the case of a homomorphism and of an isomorphism.
(a)
Verify that
(b)
Now multiply both sides of (✶) by
Warning: Do not change
Discovery 16.3. Homomorphism preserves (positive) powers.
Verify that the reasoning of Discovery 7.6 holds for homomorphisms and not just for isomorphisms.
Remark 16.2.1.
As we remarked with isomorphisms, by taking Discovery 16.2 into account, and recalling the convention that
Discovery 16.4. Homomorphism does not preserve order.
(a)
Unfortunately the reasoning of Discovery 7.7 does not hold for homomorphisms. Use one of the example homomorphisms in Discovery 16.1 to demonstrate a specific example of an element
(b)
Use Discovery 7.6 to verify that if
will hold. So what can be said about the relationship between the order of
Discovery 16.5. Homomorphism preserves inverses.
(a)
Verify both of the equalities
Warnings: Do not assume that
(b)
Explain why the equalities established in Task a imply that we must have
Apply the conclusion of Discovery 2.8 to the group element
Discovery 16.6.
Just as you did for isomorphisms (Discovery 7.9), Explain why Discovery 16.5 now lets us extend the result of Discovery 16.3 to all integers
Subsection Image and kernel
Discovery 16.7. Image is a subgroup.
This activity will guide you through using The Subgroup Test (Version 1) to verify that the image of a homomorphism
(a)
Closed under multiplication. Suppose
Your task is to now demonstrate that the product
with some element of
(b)
Closed under taking inverses. Suppose
Your task is to now demonstrate that the inverse
with some element of
Discovery 16.8. Kernel is a subgroup.
Use your preferred version of the Subgroup Test to prove that the kernel of a homomorphism
Discovery 16.9.
In the case that
Discovery 16.10.
Suppose
(a)
Prove that if
(b)
Prove the converse: If
We are already assuming that
Try to turn this into
so that you can appeal to the assumption about