This tutorial was created using ANSYS 7.0 The purpose of this tutorial is to outline the steps required to plot Vertical Deflection vs. Length of the following beam using tables, a special type of array. By plotting this data on a curve, rather than using a contour plot, finer resolution can be achieved.
This tutorial will use a steel beam 400 mm long, with a 40 mm X 60 mm cross section as shown above. It will be rigidly constrained at one end and a -2500 N load will be applied to the other.
We are going to define 2 keypoints for this beam as given in the following table:
Create a line joining Keypoints 1 and 2
For this problem we will use the BEAM3 (Beam 2D elastic) element. This element has 3 degrees of freedom (translation along the X and Y axes, and rotation about the Z axis).
In the 'Real Constants for BEAM3' window, enter the following geometric properties:
This defines a beam with a height of 40 mm and a width of 60 mm.
In the window that appears, enter the following geometric properties for steel:
For this example we will use an element edge length of 20mm.
Fix keypoint 1 (ie all DOF constrained)
The model should now look like the figure below.
It is at this point the tables come into play. Tables, a special type of array, are basically matrices that can be used to store and process data from the analysis that was just run. This example is a simplified use of tables, but they can be used for much more. For more information type help in the command line and search for 'Array Parameters'.
Since we wish to plot the verticle deflection vs length of the beam, the location and verticle deflection of each node must be recorded in the table. Therefore, it is necessary to determine how many nodes exist in the model. Utility Menu > List > Nodes... > OK. For this example there are 21 nodes. Thus the table must have at least 21 rows.
First, the horizontal location of the nodes will be recorded
Next, the vertical displacement will be recorded.
Users familiar with the way ANSYS numbers nodes will realize that node 1 will be on the far left, as it is keypoint 1, node 2 will be on the far right (keypoint 2), and the rest of the nodes are numbered sequentially from left to right. Thus, the second row in the table contains the data for the last node. This causes problems during plotting, thus the information for the last node must be moved to the final row of the table. This is why a table with 22 rows was created, to provide room to move this data.